What is l^{-1}*{log_{10}(((s^2-a^2))/((s^2)))} ?

The solution to l^{-1}*{log_{10}(((s^2-a^2))/((s^2)))} is (log_{10}(s^2-a^2)-2log_{10}(s))/l

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simplify l^{-1}*{log_{10}(((s^2-a^2))/((s^2)))}

simplify

l^{- 1} \cdot {lo g_{10} (\frac{( s ^{2} - a ^{2} )}{( s ^{2} )})}

\frac{lo g _{10} ( s ^{2} - a ^{2} ) - 2 lo g _{10} ( s )}{l}

Solution steps

l^{- 1} (lo g_{10} (\frac{s ^{2} - a ^{2}}{s ^{2}}))

Apply rule:

(a) = a

(lo g_{10} (\frac{s ^{2} - a ^{2}}{s ^{2}})) = lo g_{10} (\frac{s ^{2} - a ^{2}}{s ^{2}})

= l^{- 1} lo g_{10} (\frac{s ^{2} - a ^{2}}{s ^{2}})

Simplify

lo g_{10} (\frac{s ^{2} - a ^{2}}{s ^{2}}) : lo g_{10} (s^{2} - a^{2}) - 2 lo g_{10} (s)

= l^{- 1} (lo g_{10} (s^{2} - a^{2}) - 2 lo g_{10} (s))

Simplify

l^{- 1} (lo g_{10} (s^{2} - a^{2}) - 2 lo g_{10} (s)) : \frac{lo g _{10} ( s ^{2} - a ^{2} ) - 2 lo g _{10} ( s )}{l}

= \frac{lo g _{10} ( s ^{2} - a ^{2} ) - 2 lo g _{10} ( s )}{l}

\frac{( - 8 x )}{( - 8 x )}

2 lo g_{10} (n^{n})

(3 p - 4 q)^{3}

\frac{101}{2} \times \frac{13}{7} \times \frac{42}{5}

(a + b)^{3} - 8 \cdot (a - b)^{3}

What is l^{-1}*{log_{10}(((s^2-a^2))/((s^2)))} ?
The solution to l^{-1}*{log_{10}(((s^2-a^2))/((s^2)))} is (log_{10}(s^2-a^2)-2log_{10}(s))/l