What is log_{10}(x+2)+log_{10}(7x-1) ?

The solution to log_{10}(x+2)+log_{10}(7x-1) is log_{10}((x+2)(7x-1))

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simplify log_{10}(x+2)+log_{10}(7x-1)

simplify

lo g_{10} (x + 2) + lo g_{10} (7 x - 1)

lo g_{10} ((x + 2) (7 x - 1))

Solution steps

lo g_{10} (x + 2) + lo g_{10} (7 x - 1)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (x + 2) + lo g_{10} (7 x - 1) = lo g_{10} ((x + 2) (7 x - 1))

= lo g_{10} ((x + 2) (7 x - 1))

\frac{( 4 - 2 n )}{( n ( n + 3 ) )} - \frac{( 1 - 3 n )}{( n ( n + 3 ) )}

- 10 - 3 \times (- 4)

\frac{z ^{3}}{z ^{2}}

4 p^{2} + 2 q^{2} + p^{2} q^{2} + 8

9 a^{2} b^{2} - 25

What is log_{10}(x+2)+log_{10}(7x-1) ?
The solution to log_{10}(x+2)+log_{10}(7x-1) is log_{10}((x+2)(7x-1))