What is ((8x^3y^{-4}))/((2x^5y^2)) ?

The solution to ((8x^3y^{-4}))/((2x^5y^2)) is 4/(x^2y^6)

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simplify ((8x^3y^{-4}))/((2x^5y^2))

simplify

\frac{( 8 x ^{3} y ^{- 4} )}{( 2 x ^{5} y ^{2} )}

\frac{4}{x ^{2} y ^{6}}

Solution steps

\frac{8 x ^{3} y ^{- 4}}{2 x ^{5} y ^{2}}

Factor the number:

8 = 2 \cdot 4

= \frac{2 \cdot 4 x ^{3} y ^{- 4}}{2 x ^{5} y ^{2}}

Cancel the common factor:

2

= \frac{4 x ^{3} y ^{- 4}}{x ^{5} y ^{2}}

Simplify

\frac{x ^{3}}{x ^{5}} : \frac{1}{x ^{2}}

= \frac{4 y ^{- 4}}{x ^{2} y ^{2}}

Simplify

\frac{y ^{- 4}}{y ^{2}} : \frac{1}{y ^{6}}

= \frac{4}{x ^{2} y ^{6}}

2 x^{5} - x^{4} - 10 x^{3} + 5 x^{2} + 8 x - 4

63 a - 70

(x^{3} y^{2} z^{3})^{\frac{1}{13}}

(4 x^{4} y^{- 3})^{\frac{1}{2}}

8 x^{4} + 16 x^{3} - 4 x^{2}

What is ((8x^3y^{-4}))/((2x^5y^2)) ?
The solution to ((8x^3y^{-4}))/((2x^5y^2)) is 4/(x^2y^6)