What is ((n^2-8n+16))/((n-4)) ?

The solution to ((n^2-8n+16))/((n-4)) is n-4

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simplify ((n^2-8n+16))/((n-4))

simplify

\frac{( n ^{2} - 8 n + 16 )}{( n - 4 )}

n - 4

Solution steps

\frac{n ^{2} - 8 n + 16}{n - 4}

Factor

n^{2} - 8 n + 16 : (n - 4)^{2}

= \frac{( n - 4 ) ^{2}}{n - 4}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(n - 4)^{2} = (n - 4) (n - 4)

= \frac{( n - 4 ) ( n - 4 )}{n - 4}

Cancel the common factor:

n - 4

= n - 4

a \frac{0.1}{6} \cdot \frac{5}{9}

3 x^{2} + 6 x + 15

\frac{2}{( 7 x + 5 x )}

(m + 2 p)^{2} + (m_{3} p)^{2}

(\frac{x + 2}{x - 3}) (\frac{x - 2}{x - 3})