What is factor z^3+2z^2-68z+120 ?

The solution to factor z^3+2z^2-68z+120 is (z-2)(z-6)(z+10)

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factor z^3+2z^2-68z+120

factor

z^{3} + 2 z^{2} - 68 z + 120

(z - 2) (z - 6) (z + 10)

Solution steps

z^{3} + 2 z^{2} - 68 z + 120

Use the rational root theorem

= (z - 2) \frac{z ^{3} + 2 z ^{2} - 68 z + 120}{z - 2}

\frac{z ^{3} + 2 z ^{2} - 68 z + 120}{z - 2} = z^{2} + 4 z - 60

= (z - 2) (z^{2} + 4 z - 60)

Factor

z^{2} + 4 z - 60 : (z - 6) (z + 10)

= (z - 2) (z - 6) (z + 10)

(7 n^{5} p^{3})^{4}

e^{x} \cdot ln (x^{2})

\frac{tan ^{2} ( x )}{sec ^{5} ( x )}

i^{3} + j^{3} + k^{3}

(1.38 (18 + x^{2})^{\frac{1}{2}}) 18 - x

What is factor z^3+2z^2-68z+120 ?
The solution to factor z^3+2z^2-68z+120 is (z-2)(z-6)(z+10)