What is 6/1-x-4/1+x-8/(x^2)-1 ?

The solution to 6/1-x-4/1+x-8/(x^2)-1 is -8/(x^2)+1

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simplify 6/1-x-4/1+x-8/(x^2)-1

simplify

\frac{6}{1} - x - \frac{4}{1} + x - \frac{8}{x ^{2}} - 1

- \frac{8}{x ^{2}} + 1

Solution steps

\frac{6}{1} - x - \frac{4}{1} + x - \frac{8}{x ^{2}} - 1

Group like terms

= - x + x + \frac{6}{1} - \frac{4}{1} - \frac{8}{x ^{2}} - 1

Add similar elements:

- x + x = 0

= \frac{6}{1} - \frac{4}{1} - \frac{8}{x ^{2}} - 1

\frac{6}{1} = 6

\frac{4}{1} = 4

= 6 - 4 - \frac{8}{x ^{2}} - 1

Group like terms

= - \frac{8}{x ^{2}} + 6 - 4 - 1

Subtract the numbers:

6 - 4 - 1 = 1

= - \frac{8}{x ^{2}} + 1

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What is 6/1-x-4/1+x-8/(x^2)-1 ?
The solution to 6/1-x-4/1+x-8/(x^2)-1 is -8/(x^2)+1