What is ((2b-4))/((b^3+8)+(1)(b+2)) ?

The solution to ((2b-4))/((b^3+8)+(1)(b+2)) is (2b-4)/(b^3+b+10)

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simplify ((2b-4))/((b^3+8)+(1)(b+2))

simplify

\frac{( 2 b - 4 )}{( b ^{3} + 8 ) + ( 1 ) ( b + 2 )}

\frac{2 b - 4}{b ^{3} + b + 10}

Solution steps

\frac{2 b - 4}{( b ^{3} + 8 ) + ( 1 ) ( b + 2 )}

Simplify

(b^{3} + 8) + (1) (b + 2) : b^{3} + 8 + 1 \cdot (b + 2)

= \frac{2 b - 4}{b ^{3} + 8 + 1 \cdot ( b + 2 )}

Apply rule:

1 \cdot a = a

= \frac{2 b - 4}{b ^{3} + 8 + ( b + 2 )}

Apply rule:

a + (b + c) = a + b + c

8 + (b + 2) = 8 + b + 2

= \frac{2 b - 4}{b ^{3} + 8 + b + 2}

Simplify

b^{3} + 8 + b + 2 : b^{3} + b + 10

= \frac{2 b - 4}{b ^{3} + b + 10}

\frac{( 33.3 \cdot 1 0 ^{- 3} - x )}{( ( x ) ( x ) )}

5.1 (1 - x)^{2}

a^{2} - 1 - 2 x - x^{2}

3 x - 2 x^{4} y

x^{4} - 125 x y^{3}

What is ((2b-4))/((b^3+8)+(1)(b+2)) ?
The solution to ((2b-4))/((b^3+8)+(1)(b+2)) is (2b-4)/(b^3+b+10)