What is ((x^3-4-x+4x^2))/((x^2+3x-4)) ?

The solution to ((x^3-4-x+4x^2))/((x^2+3x-4)) is x+1

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simplify ((x^3-4-x+4x^2))/((x^2+3x-4))

simplify

\frac{( x ^{3} - 4 - x + 4 x ^{2} )}{( x ^{2} + 3 x - 4 )}

x + 1

Solution steps

\frac{x ^{3} - 4 - x + 4 x ^{2}}{x ^{2} + 3 x - 4}

Factor

x^{3} - 4 - x + 4 x^{2} : (x + 4) (x + 1) (x - 1)

= \frac{( x + 4 ) ( x + 1 ) ( x - 1 )}{x ^{2} + 3 x - 4}

Factor

x^{2} + 3 x - 4 : (x - 1) (x + 4)

= \frac{( x + 4 ) ( x + 1 ) ( x - 1 )}{( x - 1 ) ( x + 4 )}

Cancel the common factor:

x + 4

= \frac{( x + 1 ) ( x - 1 )}{x - 1}

Cancel the common factor:

x - 1

= x + 1

x^{3} + 2 x^{2} y - x y^{2} - 2 y^{3}

\frac{( 2 x ^{33} x ^{2} - 1 )}{( x ^{1} )}

\frac{( 2 - i ) \cdot ( z + 4 i )}{- 3 + i}

5 x y^{2} + 4 y^{2} x

m^{8} - 11 m^{4} n^{4} - 80 n^{8}

What is ((x^3-4-x+4x^2))/((x^2+3x-4)) ?
The solution to ((x^3-4-x+4x^2))/((x^2+3x-4)) is x+1