What is factor x^2+4x+4-y^2 ?

The solution to factor x^2+4x+4-y^2 is (x+2+y)(x+2-y)

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factor x^2+4x+4-y^2

factor

x^{2} + 4 x + 4 - y^{2}

(x + 2 + y) (x + 2 - y)

Solution steps

x^{2} + 4 x + 4 - y^{2}

Factor

x^{2} + 4 x + 4 : (x + 2)^{2}

= (x + 2)^{2} - y^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(x + 2)^{2} - y^{2} = ((x + 2) + y) ((x + 2) - y)

= ((x + 2) + y) ((x + 2) - y)

Apply rule:

(a) = a

(x + 2) = x + 2

= (x + 2 + y) (x + 2 - y)

4 x^{2} + 4^{2} - 12 x + 8 y + j

(3 z)^{4} - z^{7}

4 cot^{3} (x) + 4 cot^{2} (x) + 4 cot (x) + 4

(0.15 - x)^{2}

3 x^{2} y^{4} z x^{3} y^{- 3} z^{2}

What is factor x^2+4x+4-y^2 ?
The solution to factor x^2+4x+4-y^2 is (x+2+y)(x+2-y)