What is ((x-2)}{(x+3)}\frac{(x+1))/x ?

The solution to ((x-2)}{(x+3)}\frac{(x+1))/x is ((x-2)(x+1))/((x+3)x)

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simplify ((x-2)}{(x+3)}\frac{(x+1))/x

simplify

\frac{( x - 2 )}{( x + 3 )} \frac{( x + 1 )}{x}

\frac{( x - 2 ) ( x + 1 )}{( x + 3 ) x}

Solution steps

\frac{x - 2}{x + 3} \cdot \frac{x + 1}{x}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( x - 2 ) ( x + 1 )}{( x + 3 ) x}

(u + 2 w) (4 u - 3 w - 2)

(x + y)^{3} - (x + y)

2 x^{2} y^{3} - 4 x^{2} z

(2 x^{2} - 3 x + 2) + (- x^{2} + x - 2)

2 cos^{2} (x) + cos (x) - 1

What is ((x-2)}{(x+3)}\frac{(x+1))/x ?
The solution to ((x-2)}{(x+3)}\frac{(x+1))/x is ((x-2)(x+1))/((x+3)x)