What is (x+2)/(x+3)<= (x-1)/(x-2) ?

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(x+2)/(x+3)<= (x-1)/(x-2)

\frac{x + 2}{x + 3} \leq \frac{x - 1}{x - 2}

- 3 < x \leq - \frac{1}{2} or x > 2

Interval Notation

(- 3, - \frac{1}{2}] \cup (2, \infty)

Decimal Notation

- 3 < x \leq - 0.5 or x > 2

Solution steps

\frac{x + 2}{x + 3} \leq \frac{x - 1}{x - 2}

Rewrite in standard form

\frac{- 2 x - 1}{( x + 3 ) ( x - 2 )} \leq 0

Identify the intervals

- 3 < x \leq - \frac{1}{2} or x > 2

a^{2} - 7 a = 0

∣ a ∣ < 10

7 x - 4 = 5 x + 15

\frac{- 3 2}{2 - 5}

- 10 < - 5 k - 15 < 25

What is (x+2)/(x+3)<= (x-1)/(x-2) ?
The solution to (x+2)/(x+3)<= (x-1)/(x-2) is -3<x<=-1/2 \lor x>2