What is ((8x^2)/(12x^5))*(((6x^4)/(2x))) ?

The solution to ((8x^2)/(12x^5))*(((6x^4)/(2x))) is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((8x^2)/(12x^5))*(((6x^4)/(2x)))

simplify

(\frac{8 x ^{2}}{12 x ^{5}}) \cdot ((\frac{6 x ^{4}}{2 x}))

2

Solution steps

(\frac{8 x ^{2}}{12 x ^{5}}) ((\frac{6 x ^{4}}{2 x}))

Simplify

(\frac{8 x ^{2}}{12 x ^{5}}) ((\frac{6 x ^{4}}{2 x})) : \frac{8 x ^{2}}{12 x ^{5}} \cdot \frac{6 x ^{4}}{2 x}

= \frac{8 x ^{2}}{12 x ^{5}} \cdot \frac{6 x ^{4}}{2 x}

Cancel

\frac{8 x ^{2}}{12 x ^{5}} : \frac{2}{3 x ^{3}}

= \frac{2}{3 x ^{3}} \cdot \frac{6 x ^{4}}{2 x}

Cancel

\frac{6 x ^{4}}{2 x} : 3 x^{3}

= \frac{2}{3 x ^{3}} \cdot 3 x^{3}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \cdot 3 x ^{3}}{3 x ^{3}}

Cancel the common factor:

3

= \frac{2 x ^{3}}{x ^{3}}

Cancel the common factor:

x^{3}

= 2

(sin (x) + cos^{2} (x))^{3}

(x - 3) (2 x^{z} - x + 5)

\frac{( 3 x y )}{( x \cdot y ^{2} )}

(x^{2} + 4 x + 8)^{2} - 3 x (x^{2} + 4 x + 8) + 2 x^{2}

16 x y^{3} - 64 x y

What is ((8x^2)/(12x^5))*(((6x^4)/(2x))) ?
The solution to ((8x^2)/(12x^5))*(((6x^4)/(2x))) is 2