What is factor 10x^3-19x^2-61x-8 ?

The solution to factor 10x^3-19x^2-61x-8 is (5x+8)(2x^2-7x-1)

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factor 10x^3-19x^2-61x-8

factor

10 x^{3} - 19 x^{2} - 61 x - 8

(5 x + 8) (2 x^{2} - 7 x - 1)

Solution steps

10 x^{3} - 19 x^{2} - 61 x - 8

Use the rational root theorem

a_{0} = 8, a_{n} = 10

The dividers of

a_{0} : 1, 2, 4, 8,

The dividers of

a_{n} : 1, 2, 5, 10

Therefore, check the following rational numbers:

\pm \frac{1 , 2 , 4 , 8}{1 , 2 , 5 , 10}

- \frac{8}{5}

is a root of the expression, so factor out

5 x + 8

= (5 x + 8) \frac{10 x ^{3} - 19 x ^{2} - 61 x - 8}{5 x + 8}

\frac{10 x ^{3} - 19 x ^{2} - 61 x - 8}{5 x + 8} = 2 x^{2} - 7 x - 1

= (5 x + 8) (2 x^{2} - 7 x - 1)

r - (- 22)

64 x^{6} - 729 y^{6}

\frac{5 - ( 3 x )}{4 - 8}

a (a + 1) x^{2} + x - a (a - 1)

x^{4} + x^{2} + x

What is factor 10x^3-19x^2-61x-8 ?
The solution to factor 10x^3-19x^2-61x-8 is (5x+8)(2x^2-7x-1)