What is factor x^4+3x^3+3x^2-1 ?

The solution to factor x^4+3x^3+3x^2-1 is (x+1)(x^3+2x^2+x-1)

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factor x^4+3x^3+3x^2-1

factor

x^{4} + 3 x^{3} + 3 x^{2} - 1

(x + 1) (x^{3} + 2 x^{2} + x - 1)

Solution steps

x^{4} + 3 x^{3} + 3 x^{2} - 1

Use the rational root theorem

= (x + 1) \frac{x ^{4} + 3 x ^{3} + 3 x ^{2} - 1}{x + 1}

\frac{x ^{4} + 3 x ^{3} + 3 x ^{2} - 1}{x + 1} = x^{3} + 2 x^{2} + x - 1

= (x + 1) (x^{3} + 2 x^{2} + x - 1)

(- x^{6} \cdot y^{8})^{2}

\frac{( m )}{91 - 8809674712}

4 x (x + 5) - x (x + 5)

\frac{1}{( 1 + x ^{2} + 1 )}

- \frac{1}{4} \cdot \frac{x ^{\frac{3}{4}}}{- 2} \cdot x^{- \frac{1}{4}}

What is factor x^4+3x^3+3x^2-1 ?
The solution to factor x^4+3x^3+3x^2-1 is (x+1)(x^3+2x^2+x-1)