What is (s+2)^3-9s-18 ?

The solution to (s+2)^3-9s-18 is s^3+6s^2+3s-10

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simplify (s+2)^3-9s-18

simplify

(s + 2)^{3} - 9 s - 18

s^{3} + 6 s^{2} + 3 s - 10

Solution steps

(s + 2)^{3} - 9 s - 18

Expand

(s + 2)^{3} : s^{3} + 6 s^{2} + 12 s + 8

= s^{3} + 6 s^{2} + 12 s + 8 - 9 s - 18

Group like terms

= s^{3} + 6 s^{2} + 12 s - 9 s + 8 - 18

Add similar elements:

12 s - 9 s = 3 s

= s^{3} + 6 s^{2} + 3 s + 8 - 18

Subtract the numbers:

8 - 18 = - 10

= s^{3} + 6 s^{2} + 3 s - 10

(x - 1)^{- 4}

\frac{l cos ( t ^{\frac{1}{2}} )}{t ^{\frac{1}{2}}}

(- 120 y a z) \cdot 0.6 y u m

z^{1} - z^{2}

10 m + (- 5 m) + 14 p