What is (n+1)^2-2(n+2) ?

The solution to (n+1)^2-2(n+2) is n^2-3

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simplify (n+1)^2-2(n+2)

simplify

(n + 1)^{2} - 2 (n + 2)

n^{2} - 3

Solution steps

(n + 1)^{2} - 2 (n + 2)

Expand

(n + 1)^{2} : n^{2} + 2 n + 1

= n^{2} + 2 n + 1 - 2 (n + 2)

Expand

- 2 (n + 2) : - 2 n - 4

= n^{2} + 2 n + 1 - 2 n - 4

Group like terms

= n^{2} + 2 n - 2 n + 1 - 4

Add similar elements:

2 n - 2 n = 0

= n^{2} + 1 - 4

Subtract the numbers:

1 - 4 = - 3

= n^{2} - 3

tan (x) tan^{2} (x)

(v) (4 - 31)^{1}

2 x^{2} y - 4 x y^{2} + 6 x y

\frac{( ( 2 y ^{2} ) ^{2} )}{( 2 x ^{- 2} \cdot y ^{- 1} - 2 x ^{4} \cdot y ^{3} )}

\frac{x ^{2} + 11 x + 26}{- ( x + 3 )}