What is factor 9x^4-25x^2y^2+16y^4 ?

The solution to factor 9x^4-25x^2y^2+16y^4 is (x+y)(x-y)(3x+4y)(3x-4y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 9x^4-25x^2y^2+16y^4

factor

9 x^{4} - 25 x^{2} y^{2} + 16 y^{4}

(x + y) (x - y) (3 x + 4 y) (3 x - 4 y)

Solution steps

9 x^{4} - 25 x^{2} y^{2} + 16 y^{4}

Break the expression into groups

= (9 x^{4} - 9 x^{2} y^{2}) + (- 16 x^{2} y^{2} + 16 y^{4})

Factor out

9 x^{2}

from

9 x^{4} - 9 x^{2} y^{2} : 9 x^{2} (x^{2} - y^{2})

Factor out

- 16 y^{2}

from

- 16 x^{2} y^{2} + 16 y^{4} : - 16 y^{2} (x^{2} - y^{2})

= 9 x^{2} (x^{2} - y^{2}) - 16 y^{2} (x^{2} - y^{2})

Factor out common term

x^{2} - y^{2}

= (x^{2} - y^{2}) (9 x^{2} - 16 y^{2})

Factor

x^{2} - y^{2} : (x + y) (x - y)

= (x + y) (x - y) (9 x^{2} - 16 y^{2})

Factor

9 x^{2} - 16 y^{2} : (3 x + 4 y) (3 x - 4 y)

= (x + y) (x - y) (3 x + 4 y) (3 x - 4 y)

6.23 x 1 0^{- 8} \cdot 1 0^{- 6} 0.5

(\frac{x ^{6} + 5}{6 x ^{3}})^{3}

\frac{- 48 a ^{5} b ^{- 4}}{12 a ^{- 4} b ^{- 2}}

x^{3} + 1 - x^{2} - x

(3 x^{- 4} \cdot y^{- 6})^{- 5}

What is factor 9x^4-25x^2y^2+16y^4 ?
The solution to factor 9x^4-25x^2y^2+16y^4 is (x+y)(x-y)(3x+4y)(3x-4y)