What is factor 8x^6+27y^3 ?

The solution to factor 8x^6+27y^3 is (2x^2+3y)(4x^4-6x^2y+9y^2)

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factor 8x^6+27y^3

factor

8 x^{6} + 27 y^{3}

(2 x^{2} + 3 y) (4 x^{4} - 6 x^{2} y + 9 y^{2})

Solution steps

8 x^{6} + 27 y^{3}

Apply exponent rules

= (2 x^{2})^{3} + (3 y)^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(2 x^{2})^{3} + (3 y)^{3} = (2 x^{2} + 3 y) ((2 x^{2})^{2} - 2 x^{2} \cdot 3 y + (3 y)^{2})

= (2 x^{2} + 3 y) ((2 x^{2})^{2} - 2 x^{2} \cdot 3 y + (3 y)^{2})

Simplify

(2 x^{2})^{2} - 2 x^{2} \cdot 3 y + (3 y)^{2} : 4 x^{4} - 6 x^{2} y + 9 y^{2}

= (2 x^{2} + 3 y) (4 x^{4} - 6 x^{2} y + 9 y^{2})

2 x^{2} + 10 x y

\frac{1}{cos ^{2} ( x )} \frac{1}{x}

(2 r + 1)^{3}

lo g_{5} (5^{a})

t (s) 1233 v (\frac{m}{s}) 4812

What is factor 8x^6+27y^3 ?
The solution to factor 8x^6+27y^3 is (2x^2+3y)(4x^4-6x^2y+9y^2)