What is (1+x)^{-2}+(1+x)^{-4} ?

The solution to (1+x)^{-2}+(1+x)^{-4} is 1/((1+x)^2)+1/((1+x)^4)

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simplify (1+x)^{-2}+(1+x)^{-4}

simplify

(1 + x)^{- 2} + (1 + x)^{- 4}

\frac{1}{( 1 + x ) ^{2}} + \frac{1}{( 1 + x ) ^{4}}

Solution steps

(1 + x)^{- 2} + (1 + x)^{- 4}

(1 + x)^{- 2} = \frac{1}{( 1 + x ) ^{2}}

(1 + x)^{- 4} = \frac{1}{( 1 + x ) ^{4}}

= \frac{1}{( 1 + x ) ^{2}} + \frac{1}{( 1 + x ) ^{4}}

\frac{9}{x} - \frac{8}{t}

(3 a + 4 z)^{7}

9 c^{0} (0.8)^{0} (1 - 0.6)^{9}

\frac{( b ^{4} )}{( 2 b )}

(\frac{a + 1}{a}) - (\frac{a - 1}{a})

What is (1+x)^{-2}+(1+x)^{-4} ?
The solution to (1+x)^{-2}+(1+x)^{-4} is 1/((1+x)^2)+1/((1+x)^4)