What is factor 3u^3-4u^2-12u+16 ?

The solution to factor 3u^3-4u^2-12u+16 is (3u-4)(u+2)(u-2)

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factor 3u^3-4u^2-12u+16

factor

3 u^{3} - 4 u^{2} - 12 u + 16

(3 u - 4) (u + 2) (u - 2)

Solution steps

3 u^{3} - 4 u^{2} - 12 u + 16

= (3 u^{3} - 4 u^{2}) + (- 12 u + 16)

Factor out

u^{2}

from

3 u^{3} - 4 u^{2} : u^{2} (3 u - 4)

Factor out

- 4

from

- 12 u + 16 : - 4 (3 u - 4)

= u^{2} (3 u - 4) - 4 (3 u - 4)

Factor out common term

3 u - 4

= (3 u - 4) (u^{2} - 4)

Factor

u^{2} - 4 : (u + 2) (u - 2)

= (3 u - 4) (u + 2) (u - 2)

\frac{7 ^{n} + 7 ^{n} - 1}{7 ^{n} + 1 - 7 ^{n}}

20 - \frac{( p \cdot q ^{3} \cdot r )}{( p - q + r )}

\frac{( x ^{120} - y ^{180} )}{( x ^{2} - y ^{3} )}

3 x - 1 f (x) v^{5}

6 (y^{5})^{0}

What is factor 3u^3-4u^2-12u+16 ?
The solution to factor 3u^3-4u^2-12u+16 is (3u-4)(u+2)(u-2)