What is (f''(1)ln(x^2))/(e^2x) ?

The solution to (f''(1)ln(x^2))/(e^2x) is (2ln(x)f''(1))/(e^2x)

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simplify (f''(1)ln(x^2))/(e^2x)

simplify

\frac{f ^{''} ( 1 ) ln ( x ^{2} )}{e ^{2} x}

\frac{2 ln ( x ) f '' ( 1 )}{e ^{2} x}

Solution steps

\frac{f ^{''} ( 1 ) ln ( x ^{2} )}{e ^{2} x}

Simplify

ln (x^{2}) : 2 ln (x)

= \frac{2 ln ( x ) f ^{''} ( 1 )}{e ^{2} x}

(5 x - 2 x) 2

2 (x^{2})^{x}

(\frac{a ^{4} b ^{2}}{a ^{- 3} b ^{9}})^{4}

\frac{1}{u} + \frac{1}{v}

\frac{( 3 x + 4 )}{2} - \frac{( 5 x - 2 )}{3}

What is (f''(1)ln(x^2))/(e^2x) ?
The solution to (f''(1)ln(x^2))/(e^2x) is (2ln(x)f''(1))/(e^2x)