What is factor a^9-b^9 ?

The solution to factor a^9-b^9 is (a-b)(a^2+ab+b^2)(a^6+a^3b^3+b^6)

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factor a^9-b^9

factor

a^{9} - b^{9}

(a - b) (a^{2} + ab + b^{2}) (a^{6} + a^{3} b^{3} + b^{6})

Solution steps

a^{9} - b^{9}

Apply exponent rules

= (a^{3})^{3} - (b^{3})^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(a^{3})^{3} - (b^{3})^{3} = (a^{3} - b^{3}) ((a^{3})^{2} + a^{3} b^{3} + (b^{3})^{2})

= (a^{3} - b^{3}) ((a^{3})^{2} + a^{3} b^{3} + (b^{3})^{2})

Simplify

(a^{3})^{2} + a^{3} b^{3} + (b^{3})^{2} : a^{6} + a^{3} b^{3} + b^{6}

= (a^{3} - b^{3}) (a^{6} + a^{3} b^{3} + b^{6})

Factor

a^{3} - b^{3} : (a - b) (a^{2} + ab + b^{2})

= (a - b) (a^{2} + ab + b^{2}) (a^{6} + a^{3} b^{3} + b^{6})

x y - y + x - 1

(2 x + 3)^{5} \cdot (3 - x)^{4}

(2 a^{2} + 4)^{4}

\frac{1}{25} a^{2} b^{2} - 25

- 4.5 y - 8.2

What is factor a^9-b^9 ?
The solution to factor a^9-b^9 is (a-b)(a^2+ab+b^2)(a^6+a^3b^3+b^6)