What is ((x^3-49x))/((x^4-7x^3)) ?

The solution to ((x^3-49x))/((x^4-7x^3)) is (x+7)/(x^2)

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simplify ((x^3-49x))/((x^4-7x^3))

simplify

\frac{( x ^{3} - 49 x )}{( x ^{4} - 7 x ^{3} )}

\frac{x + 7}{x ^{2}}

Solution steps

\frac{x ^{3} - 49 x}{x ^{4} - 7 x ^{3}}

Factor

x^{3} - 49 x : x (x + 7) (x - 7)

= \frac{x ( x + 7 ) ( x - 7 )}{x ^{4} - 7 x ^{3}}

Factor

x^{4} - 7 x^{3} : x^{3} (x - 7)

= \frac{x ( x + 7 ) ( x - 7 )}{x ^{3} ( x - 7 )}

Cancel the common factor:

x - 7

= \frac{x ( x + 7 )}{x ^{3}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{3} = x x^{2}

= \frac{x ( x + 7 )}{x x ^{2}}

Cancel the common factor:

x

= \frac{x + 7}{x ^{2}}

cos^{2} (x) sec^{2} (x)

512 x^{3} - 27 y^{3}

- 24 + (- 19) \cdot x^{37}

\frac{( 7 + ( \frac{5}{7} \cdot x ) )}{( \frac{7}{x} )}

(i) (a \cdot b^{3})^{7} \cdot (\frac{a}{b})^{34}

What is ((x^3-49x))/((x^4-7x^3)) ?
The solution to ((x^3-49x))/((x^4-7x^3)) is (x+7)/(x^2)