What is the answer to 4(2m-1)+3m=2(4m-1)-(2-m) ?

The answer to 4(2m-1)+3m=2(4m-1)-(2-m) is m=0

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4(2m-1)+3m=2(4m-1)-(2-m)

4 (2 m - 1) + 3 m = 2 (4 m - 1) - (2 - m)

m = 0

Solution steps

4 (2 m - 1) + 3 m = 2 (4 m - 1) - (2 - m)

Expand

4 (2 m - 1) + 3 m : 11 m - 4

Expand

2 (4 m - 1) - (2 - m) : 9 m - 4

11 m - 4 = 9 m - 4

Move

4

to the right side

11 m = 9 m

Move

9 m

to the left side

2 m = 0

Divide both sides by

2

m = 0

- 4 = n - 8

\frac{( 4 m ^{4} ) ^{2}}{12 m ^{5}}

a (4 a + 5) - 8 = 0

\frac{1}{3} (3 j + 6)

What is the answer to 4(2m-1)+3m=2(4m-1)-(2-m) ?
The answer to 4(2m-1)+3m=2(4m-1)-(2-m) is m=0
Solve for m: 4(2m-1)+3m=2(4m-1)-(2-m)
The solution is m=0