What is (((sqrt(3x)-y))/2)^2 ?

The solution to (((sqrt(3x)-y))/2)^2 is (3x-2sqrt(3)ysqrt(x)+y^2)/4

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simplify (((sqrt(3x)-y))/2)^2

simplify

(\frac{( 3 x - y )}{2})^{2}

\frac{3 x - 2 3 y x + y ^{2}}{4}

Solution steps

(\frac{3 x - y}{2})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 x - y ) ^{2}}{2 ^{2}}

2^{2} = 4

= \frac{( 3 x - y ) ^{2}}{4}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{( 3 x - y ) ^{2}}{4}

Expand

(3 x - y)^{2} : 3 x - 23 y x + y^{2}

= \frac{3 x - 2 3 y x + y ^{2}}{4}

(6 x^{5} + 5)^{3}

8 \frac{( 1 - sin ( a ) )}{( 1 + sin ( a ) )}

(\frac{3}{x} + \frac{4}{y})^{3}

207 x + 429 x - 12

(c - 4)^{3}

What is (((sqrt(3x)-y))/2)^2 ?
The solution to (((sqrt(3x)-y))/2)^2 is (3x-2sqrt(3)ysqrt(x)+y^2)/4