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Popular >

simplify (2a^3b^2)^{-4}

Solution

simplify

(2 a^{3} b^{2})^{- 4}

Solution

\frac{1}{16 a ^{12} b ^{8}}

Solution steps

(2 a^{3} b^{2})^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(2 a^{3} b^{2})^{- 4} = \frac{1}{( 2 a ^{3} b ^{2} ) ^{4}}

= \frac{1}{( 2 a ^{3} b ^{2} ) ^{4}}

Simplify

(2 a^{3} b^{2})^{4} : 16 a^{12} b^{8}

= \frac{1}{16 a ^{12} b ^{8}}

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Frequently Asked Questions (FAQ)

What is (2a^3b^2)^{-4} ?
The solution to (2a^3b^2)^{-4} is 1/(16a^{12)b^8}