What is factor 12x^3-25x^2-38x+15 ?

The solution to factor 12x^3-25x^2-38x+15 is (3x-1)(4x+5)(x-3)

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factor 12x^3-25x^2-38x+15

factor

12 x^{3} - 25 x^{2} - 38 x + 15

(3 x - 1) (4 x + 5) (x - 3)

Solution steps

12 x^{3} - 25 x^{2} - 38 x + 15

Use the rational root theorem

= (3 x - 1) \frac{12 x ^{3} - 25 x ^{2} - 38 x + 15}{3 x - 1}

\frac{12 x ^{3} - 25 x ^{2} - 38 x + 15}{3 x - 1} = 4 x^{2} - 7 x - 15

= (3 x - 1) (4 x^{2} - 7 x - 15)

Factor

4 x^{2} - 7 x - 15 : (4 x + 5) (x - 3)

= (3 x - 1) (4 x + 5) (x - 3)

12 x^{3} \cdot y - 8 x^{5} \cdot y^{2} + 4 x^{2} \cdot y^{5}

lo g_{10} (\frac{x + 1}{x})

\frac{( x ^{\frac{2}{3}} )}{( x ^{- \frac{1}{3}} )}

16 x^{4} + 8 x^{2} \cdot y + y^{2}

3 x + (- x + 2 y - z)

What is factor 12x^3-25x^2-38x+15 ?
The solution to factor 12x^3-25x^2-38x+15 is (3x-1)(4x+5)(x-3)