What is factor x^5+4x^4-10x^2-x+6 ?

The solution to factor x^5+4x^4-10x^2-x+6 is (x-1)^2(x+1)(x+2)(x+3)

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factor x^5+4x^4-10x^2-x+6

factor

x^{5} + 4 x^{4} - 10 x^{2} - x + 6

(x - 1)^{2} (x + 1) (x + 2) (x + 3)

Solution steps

x^{5} + 4 x^{4} - 10 x^{2} - x + 6

Use the rational root theorem

= (x - 1) \frac{x ^{5} + 4 x ^{4} - 10 x ^{2} - x + 6}{x - 1}

\frac{x ^{5} + 4 x ^{4} - 10 x ^{2} - x + 6}{x - 1} = x^{4} + 5 x^{3} + 5 x^{2} - 5 x - 6

= (x - 1) (x^{4} + 5 x^{3} + 5 x^{2} - 5 x - 6)

Factor

x^{4} + 5 x^{3} + 5 x^{2} - 5 x - 6 : (x - 1) (x + 1) (x + 2) (x + 3)

= (x - 1) (x - 1) (x + 1) (x + 2) (x + 3)

Apply exponent rule:

aa = a^{2}

(x - 1) (x - 1) = (x - 1)^{2}

= (x - 1)^{2} (x + 1) (x + 2) (x + 3)

(2 y^{4} - 1)^{6}

\frac{( 8 m ^{2} - 2 )}{( 2 m ^{2} )}

3 a^{5} b - a^{3} c

- 4 y - 3

l^{- 1} \cdot (\frac{3}{( s ^{5} )})

What is factor x^5+4x^4-10x^2-x+6 ?
The solution to factor x^5+4x^4-10x^2-x+6 is (x-1)^2(x+1)(x+2)(x+3)