What is 2(cos(o)+i*sin(0)) ?

The solution to 2(cos(o)+i*sin(0)) is 2cos(o)+2sin(0)i

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simplify 2(cos(o)+i*sin(0))

simplify

2 (cos (o) + i \cdot sin (0))

2 cos (o) + 2 sin (0) i

Solution steps

2 (cos (o) + i sin (0))

Apply the distributive law:

a (b + c) = ab + a c

2 (cos (o) + i sin (0)) = 2 cos (o) + 2 i sin (0)

= 2 cos (o) + 2 i sin (0)

Rewrite in standard complex form:

2 cos (o) + 2 sin (0) i

= 2 cos (o) + 2 sin (0) i

(2^{3} \cdot x^{7})^{0}

(4^{3})^{n} + (4^{3})^{n}

sec^{2} (x) cot (x) cos (x)

2 x^{2} + 2 y^{2} + 8 x + \frac{7}{0}

\frac{( 2 ^{n + 4} \cdot 4 \cdot 2 ^{n - 1} )}{( 2 ^{n} )}

What is 2(cos(o)+i*sin(0)) ?
The solution to 2(cos(o)+i*sin(0)) is 2cos(o)+2sin(0)i