What is expand 5(x-3)(x^2+4x+1) ?

The solution to expand 5(x-3)(x^2+4x+1) is 5x^3+5x^2-55x-15

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expand 5(x-3)(x^2+4x+1)

expand

5 (x - 3) (x^{2} + 4 x + 1)

5 x^{3} + 5 x^{2} - 55 x - 15

Solution steps

5 (x - 3) (x^{2} + 4 x + 1)

Expand

5 (x - 3) : 5 x - 15

= (5 x - 15) (x^{2} + 4 x + 1)

Distribute parentheses

= 5 x x^{2} + 5 x \cdot 4 x + 5 x \cdot 1 - 15 x^{2} - 15 \cdot 4 x - 15 \cdot 1

Simplify

5 x x^{2} + 5 x \cdot 4 x + 5 x \cdot 1 - 15 x^{2} - 15 \cdot 4 x - 15 \cdot 1 : 5 x^{3} + 5 x^{2} - 55 x - 15

= 5 x^{3} + 5 x^{2} - 55 x - 15

1 + x^{2} y^{2} + x^{2} + y^{2}

(1 + 2 a)^{5}

b^{2} c^{0}

\frac{( ( - sin ( x ) ) - ( \frac{c o s ( x )}{x} ) )}{cos ^{2} ( x )}

- \frac{56}{9} y - \frac{5}{6}

What is expand 5(x-3)(x^2+4x+1) ?
The solution to expand 5(x-3)(x^2+4x+1) is 5x^3+5x^2-55x-15