What is (xy^{-1})x^{-3}y^0 ?

The solution to (xy^{-1})x^{-3}y^0 is 1/(yx^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (xy^{-1})x^{-3}y^0

simplify

(x y^{- 1}) x^{- 3} y^{0}

\frac{1}{y x ^{2}}

Solution steps

(x y^{- 1}) x^{- 3} y^{0}

Simplify

x y^{- 1} : \frac{x}{y}

= \frac{x}{y} x^{- 3} y^{0}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 3} = \frac{1}{x ^{3}}

= \frac{x}{y} \cdot \frac{1}{x ^{3}} y^{0}

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

y^{0} = 1

= \frac{x}{y} \cdot \frac{1}{x ^{3}} \cdot 1

Apply rule:

a \cdot 1 = a

= \frac{x}{y} \cdot \frac{1}{x ^{3}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{x \cdot 1}{y x ^{3}}

Apply rule:

a \cdot 1 = a

x \cdot 1 = x

= \frac{x}{y x ^{3}}

Simplify

\frac{x}{x ^{3}} : \frac{1}{x ^{2}}

= \frac{1}{y x ^{2}}

\frac{1}{4} x + \frac{2}{5} x

x^{2} + 4 y - y^{2} - 4 x

(\frac{a}{1} + \frac{1}{b}) \cdot (b + \frac{1}{a})

5 y^{2} + 33 x y - 14 y^{2}

- 6 (- 2 u + 5.2)