What is 1/((2^x))+1/((2^x))+1/((2^x))+1/((2^x)) ?

The solution to 1/((2^x))+1/((2^x))+1/((2^x))+1/((2^x)) is 2^{2-x}

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simplify 1/((2^x))+1/((2^x))+1/((2^x))+1/((2^x))

simplify

\frac{1}{( 2 ^{x} )} + \frac{1}{( 2 ^{x} )} + \frac{1}{( 2 ^{x} )} + \frac{1}{( 2 ^{x} )}

2^{2 - x}

Solution steps

\frac{1}{2 ^{x}} + \frac{1}{2 ^{x}} + \frac{1}{2 ^{x}} + \frac{1}{2 ^{x}}

Join

\frac{1}{2 ^{x}} + \frac{1}{2 ^{x}} + \frac{1}{2 ^{x}} + \frac{1}{2 ^{x}} : 2^{2 - x}

= 2^{2 - x}

1453.5 (9.6 + 18.4 y + 597.2 y) - 28.5

(b + c) 3

(5 x^{2} \cdot y^{2} \cdot m^{3} \cdot n)^{4}

\frac{25}{4} x^{2} - \frac{y ^{2}}{9}

(x^{2} - 5)^{- 1}

What is 1/((2^x))+1/((2^x))+1/((2^x))+1/((2^x)) ?
The solution to 1/((2^x))+1/((2^x))+1/((2^x))+1/((2^x)) is 2^{2-x}