What is 10cos^2(x)-6sin(x)cos(x)+2sin^2(x) ?

The solution to 10cos^2(x)-6sin(x)cos(x)+2sin^2(x) is 10cos^2(x)-3sin(2x)+2sin^2(x)

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simplify 10cos^2(x)-6sin(x)cos(x)+2sin^2(x)

simplify

10 cos^{2} (x) - 6 sin (x) cos (x) + 2 sin^{2} (x)

10 cos^{2} (x) - 3 sin (2 x) + 2 sin^{2} (x)

Solution steps

10 cos^{2} (x) - 6 sin (x) cos (x) + 2 sin^{2} (x)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

sin (x) cos (x) = \frac{sin ( 2 x )}{2}

= 6 \cdot \frac{sin ( 2 x )}{2}

Simplify

6 \cdot \frac{sin ( 2 x )}{2} : 3 sin (2 x)

= 10 cos^{2} (x) - 3 sin (2 x) + 2 sin^{2} (x)

(2 x + 5) 50

64 (m + 2)^{3} - w^{3}

(2 x^{6})^{3}

lo g_{2} (x) y - lo g_{2} (x^{2})

\frac{( \frac{1}{a} + \frac{1}{( b + c )} )}{( \frac{1}{a} - \frac{1}{( b + c )} )}

What is 10cos^2(x)-6sin(x)cos(x)+2sin^2(x) ?
The solution to 10cos^2(x)-6sin(x)cos(x)+2sin^2(x) is 10cos^2(x)-3sin(2x)+2sin^2(x)