What is log_{4}(x+3)+log_{4}(x-3)-2 ?

The solution to log_{4}(x+3)+log_{4}(x-3)-2 is log_{4}((x+3)(x-3))-2

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simplify log_{4}(x+3)+log_{4}(x-3)-2

simplify

lo g_{4} (x + 3) + lo g_{4} (x - 3) - 2

lo g_{4} ((x + 3) (x - 3)) - 2

Solution steps

lo g_{4} (x + 3) + lo g_{4} (x - 3) - 2

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{4} (x + 3) + lo g_{4} (x - 3) = lo g_{4} ((x + 3) (x - 3))

= lo g_{4} ((x + 3) (x - 3)) - 2

(h) 1 6^{\frac{- 1}{2}}

(5 x^{4} \cdot y^{- 3})^{- 2}

x^{8} + 4

(2 v - 1)^{3}

(x^{2} - 0.1)^{2}

What is log_{4}(x+3)+log_{4}(x-3)-2 ?
The solution to log_{4}(x+3)+log_{4}(x-3)-2 is log_{4}((x+3)(x-3))-2