What is ((z^2-9))/((z^2-6z+9)) ?

The solution to ((z^2-9))/((z^2-6z+9)) is (z+3)/(z-3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((z^2-9))/((z^2-6z+9))

simplify

\frac{( z ^{2} - 9 )}{( z ^{2} - 6 z + 9 )}

\frac{z + 3}{z - 3}

Solution steps

\frac{z ^{2} - 9}{z ^{2} - 6 z + 9}

Factor

z^{2} - 9 : (z + 3) (z - 3)

= \frac{( z + 3 ) ( z - 3 )}{z ^{2} - 6 z + 9}

Factor

z^{2} - 6 z + 9 : (z - 3)^{2}

= \frac{( z + 3 ) ( z - 3 )}{( z - 3 ) ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(z - 3)^{2} = (z - 3) (z - 3)

= \frac{( z + 3 ) ( z - 3 )}{( z - 3 ) ( z - 3 )}

Cancel the common factor:

z - 3

= \frac{z + 3}{z - 3}

(\frac{2}{3} \cdot x - \frac{1}{4} \cdot y)^{2}

2 x + 4 + 5 x + 7

x^{- 6} n

cos^{6} (a) - sin^{6} (a)

\frac{( 4 x ^{12} + 2 x ^{6} )}{( 4 x ^{9} )}

What is ((z^2-9))/((z^2-6z+9)) ?
The solution to ((z^2-9))/((z^2-6z+9)) is (z+3)/(z-3)