What is ((3x^2+16x+5))/((9x^2-1)) ?

The solution to ((3x^2+16x+5))/((9x^2-1)) is (x+5)/(3x-1)

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simplify ((3x^2+16x+5))/((9x^2-1))

simplify

\frac{( 3 x ^{2} + 16 x + 5 )}{( 9 x ^{2} - 1 )}

\frac{x + 5}{3 x - 1}

Solution steps

\frac{3 x ^{2} + 16 x + 5}{9 x ^{2} - 1}

Factor

3 x^{2} + 16 x + 5 : (3 x + 1) (x + 5)

= \frac{( 3 x + 1 ) ( x + 5 )}{9 x ^{2} - 1}

Factor

9 x^{2} - 1 : (3 x + 1) (3 x - 1)

= \frac{( 3 x + 1 ) ( x + 5 )}{( 3 x + 1 ) ( 3 x - 1 )}

Cancel the common factor:

3 x + 1

= \frac{x + 5}{3 x - 1}

(2 n + 1)^{5}

(5 x^{2} y + 2 x)^{3}

7 y^{2} - \frac{11}{3} y - \frac{2}{3}

9 x^{2} - 12 x + 3

68 x^{25} + 68 x^{5}

What is ((3x^2+16x+5))/((9x^2-1)) ?
The solution to ((3x^2+16x+5))/((9x^2-1)) is (x+5)/(3x-1)