What is ((x^2-y^2))/(2x-2y) ?

The solution to ((x^2-y^2))/(2x-2y) is (x+y)/2

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simplify ((x^2-y^2))/(2x-2y)

simplify

\frac{( x ^{2} - y ^{2} )}{2 x - 2 y}

\frac{x + y}{2}

Solution steps

\frac{x ^{2} - y ^{2}}{2 x - 2 y}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

x^{2} - y^{2} = (x + y) (x - y)

= \frac{( x + y ) ( x - y )}{2 x - 2 y}

Factor out common term

2

= \frac{( x + y ) ( x - y )}{2 ( x - y )}

Cancel the common factor:

x - y

= \frac{x + y}{2}

(\frac{1 - 1}{n})^{n}

\frac{x}{12 a + b + 2 x ^{12} a ^{11} + b}

(w^{5} x)^{2}

\frac{6}{( 4 + x )}

x^{2} - 24 x - 180