What is ((x^4-y^4))/((x+y)) ?

The solution to ((x^4-y^4))/((x+y)) is (x^2+y^2)(x-y)

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simplify ((x^4-y^4))/((x+y))

simplify

\frac{( x ^{4} - y ^{4} )}{( x + y )}

(x^{2} + y^{2}) (x - y)

Solution steps

\frac{x ^{4} - y ^{4}}{x + y}

x^{4} = (x^{2})^{2}

y^{4} = (y^{2})^{2}

= \frac{( x ^{2} ) ^{2} - ( y ^{2} ) ^{2}}{x + y}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(x^{2})^{2} - (y^{2})^{2} = (x^{2} + y^{2}) (x^{2} - y^{2})

= \frac{( x ^{2} + y ^{2} ) ( x ^{2} - y ^{2} )}{x + y}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

x^{2} - y^{2} = (x + y) (x - y)

= \frac{( x ^{2} + y ^{2} ) ( x + y ) ( x - y )}{x + y}

Cancel the common factor:

x + y

= (x^{2} + y^{2}) (x - y)

1.6 a + 4 x - 2.8 a - 7.5 x

(3 x + 1)^{2} - (3 x + 2) (3 x - 1)

(i) 6 x^{3} + 7 x^{2} - x - 2

(9 x^{3} \cdot y^{5})^{2} \cdot (5 x^{5} \cdot y^{3})^{3}

w^{- 2} 9

What is ((x^4-y^4))/((x+y)) ?
The solution to ((x^4-y^4))/((x+y)) is (x^2+y^2)(x-y)