What is 2(5x^2-7)-3(x^2-4x+1) ?

The solution to 2(5x^2-7)-3(x^2-4x+1) is 7x^2+12x-17

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simplify 2(5x^2-7)-3(x^2-4x+1)

simplify

2 (5 x^{2} - 7) - 3 (x^{2} - 4 x + 1)

7 x^{2} + 12 x - 17

Solution steps

2 (5 x^{2} - 7) - 3 (x^{2} - 4 x + 1)

Expand

2 (5 x^{2} - 7) : 10 x^{2} - 14

= 10 x^{2} - 14 - 3 (x^{2} - 4 x + 1)

Expand

- 3 (x^{2} - 4 x + 1) : - 3 x^{2} + 12 x - 3

= 10 x^{2} - 14 - 3 x^{2} + 12 x - 3

Group like terms

= 10 x^{2} - 3 x^{2} + 12 x - 14 - 3

Add similar elements:

10 x^{2} - 3 x^{2} = 7 x^{2}

= 7 x^{2} + 12 x - 14 - 3

Subtract the numbers:

- 14 - 3 = - 17

= 7 x^{2} + 12 x - 17

f (x) arcsin (x^{2})

\frac{cos ^{2} ( a ) - a}{2 - 1}

3 a^{2} \cdot (5 a)^{- 2}

\frac{( 4 r ^{6} + 3 r ^{4} - 2 r ^{2} )}{2 r}

c^{1} v + c^{2}

What is 2(5x^2-7)-3(x^2-4x+1) ?
The solution to 2(5x^2-7)-3(x^2-4x+1) is 7x^2+12x-17