What is (x^2-4x)(x^2-4x-1)-20 ?

The solution to (x^2-4x)(x^2-4x-1)-20 is x^4-8x^3+15x^2+4x-20

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simplify (x^2-4x)(x^2-4x-1)-20

simplify

(x^{2} - 4 x) (x^{2} - 4 x - 1) - 20

x^{4} - 8 x^{3} + 15 x^{2} + 4 x - 20

Solution steps

(x^{2} - 4 x) (x^{2} - 4 x - 1) - 20

Distribute parentheses

= x^{2} x^{2} + x^{2} (- 4 x) + x^{2} (- 1) - 4 x x^{2} - 4 x (- 4 x) - 4 x (- 1) - 20

Simplify

x^{2} x^{2} + x^{2} (- 4 x) + x^{2} (- 1) - 4 x x^{2} - 4 x (- 4 x) - 4 x (- 1) : x^{4} - 8 x^{3} + 15 x^{2} + 4 x

= x^{4} - 8 x^{3} + 15 x^{2} + 4 x - 20

\frac{\frac{1}{5}}{cos ( x )}

(a + a)^{2}

(8) \cdot v^{2} + 4 3 v - 15

\frac{1}{( ( 5 ^{2} \cdot a ^{- 6} ) ^{- 2} )}

\frac{22 f ^{23}}{44}

What is (x^2-4x)(x^2-4x-1)-20 ?
The solution to (x^2-4x)(x^2-4x-1)-20 is x^4-8x^3+15x^2+4x-20