What is factor sin^4(x)-1 ?

The solution to factor sin^4(x)-1 is (sin^2(x)+1)(sin(x)+1)(sin(x)-1)

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factor sin^4(x)-1

factor

sin^{4} (x) - 1

(sin^{2} (x) + 1) (sin (x) + 1) (sin (x) - 1)

Solution steps

sin^{4} (x) - 1

sin^{4} (x) = (sin^{2} (x))^{2}

1 = 1^{2}

= (sin^{2} (x))^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(sin^{2} (x))^{2} - 1^{2} = (sin^{2} (x) + 1) (sin^{2} (x) - 1)

= (sin^{2} (x) + 1) (sin^{2} (x) - 1)

Factor

sin^{2} (x) - 1 : (sin (x) + 1) (sin (x) - 1)

= (sin^{2} (x) + 1) (sin (x) + 1) (sin (x) - 1)

25 x^{2} - 100 x \cdot y^{2} + 100 y^{4}

\frac{\frac{1}{10} v}{v}

x^{2} ln (y^{3})

\frac{( 4 b ^{2} \cdot 2 b ^{3} )}{( 8 b )}

\frac{( x ^{3} + 2 x ^{2} + 3 x )}{2 \cdot x}

What is factor sin^4(x)-1 ?
The solution to factor sin^4(x)-1 is (sin^2(x)+1)(sin(x)+1)(sin(x)-1)