What is log_{10}(n+1)-log_{10}(n) ?

The solution to log_{10}(n+1)-log_{10}(n) is log_{10}((n+1)/n)

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simplify log_{10}(n+1)-log_{10}(n)

simplify

lo g_{10} (n + 1) - lo g_{10} (n)

lo g_{10} (\frac{n + 1}{n})

Solution steps

lo g_{10} (n + 1) - lo g_{10} (n)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (n + 1) - lo g_{10} (n) = lo g_{10} (\frac{n + 1}{n})

= lo g_{10} (\frac{n + 1}{n})

4 x y + 7 x y + (- 2 x y)

\frac{7 x ^{7} + 5 x ^{2}}{5 x}

2 b + 6 c + 2 a

10 + 512 x^{6}

\frac{( 2 x + y + 4 )}{2}

What is log_{10}(n+1)-log_{10}(n) ?
The solution to log_{10}(n+1)-log_{10}(n) is log_{10}((n+1)/n)