What is (x^2)/((\frac{(1+x)){(1-x)})} ?

The solution to (x^2)/((\frac{(1+x)){(1-x)})} is (x^2(1-x))/(1+x)

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simplify (x^2)/((\frac{(1+x)){(1-x)})}

simplify

\frac{x ^{2}}{( \frac{( 1 + x )}{( 1 - x )} )}

\frac{x ^{2} ( 1 - x )}{1 + x}

Solution steps

\frac{x ^{2}}{\frac{1 + x}{1 - x}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{x ^{2} ( 1 - x )}{1 + x}

(i) \cdot x^{x^{2}}

(\frac{x - 1}{2 x ^{2} y})^{2}

\frac{( 1 + x + x ^{2} - 1 )}{x}

- 2 y + 6

11 x^{2} y^{2} - 5 x y + 2 x

What is (x^2)/((\frac{(1+x)){(1-x)})} ?
The solution to (x^2)/((\frac{(1+x)){(1-x)})} is (x^2(1-x))/(1+x)