What is factor 4x^3-4x^2-21x-9 ?

The solution to factor 4x^3-4x^2-21x-9 is (2x+1)(2x+3)(x-3)

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factor 4x^3-4x^2-21x-9

factor

4 x^{3} - 4 x^{2} - 21 x - 9

(2 x + 1) (2 x + 3) (x - 3)

Solution steps

4 x^{3} - 4 x^{2} - 21 x - 9

Use the rational root theorem

= (2 x + 1) \frac{4 x ^{3} - 4 x ^{2} - 21 x - 9}{2 x + 1}

\frac{4 x ^{3} - 4 x ^{2} - 21 x - 9}{2 x + 1} = 2 x^{2} - 3 x - 9

= (2 x + 1) (2 x^{2} - 3 x - 9)

Factor

2 x^{2} - 3 x - 9 : (2 x + 3) (x - 3)

= (2 x + 1) (2 x + 3) (x - 3)

(2 p + q) (p - 2 q + 3 r) - (p - 3 q) (- 3 p + q - 2 r)

\frac{lo g _{a^{2}} ( b )}{( lo g _{a} ( b ^{2} ) )}

2 lo g_{10} (x^{5})

\frac{\frac{143}{2}}{x} - \frac{1}{4} - \frac{1}{12}

80 - 4 x

What is factor 4x^3-4x^2-21x-9 ?
The solution to factor 4x^3-4x^2-21x-9 is (2x+1)(2x+3)(x-3)