What are the solutions to the equation 3t^2-14t+5=0 ?

The solutions to the equation 3t^2-14t+5=0 are t=(7+sqrt(34))/3 ,t=(7-sqrt(34))/3

Find the zeros of 3t^2-14t+5=0

The zeros of 3t^2-14t+5=0 are t=(7+sqrt(34))/3 ,t=(7-sqrt(34))/3

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3 t^{2} - 14 t + 5 = 0

t = \frac{7 + 34}{3}, t = \frac{7 - 34}{3}

Decimal Notation

t = 4.27698 \dots, t = 0.38968 \dots

Solution steps

3 t^{2} - 14 t + 5 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

(- 14)^{2} - 4 \cdot 3 \cdot 5 = 234

t_{1, 2} = \frac{- ( - 14 ) \pm 2 34}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 14 ) + 2 34}{2 \cdot 3}, t_{2} = \frac{- ( - 14 ) - 2 34}{2 \cdot 3}

t = \frac{- ( - 14 ) + 2 34}{2 \cdot 3} : \frac{7 + 34}{3}

t = \frac{- ( - 14 ) - 2 34}{2 \cdot 3} : \frac{7 - 34}{3}

The solutions to the quadratic equation are:

t = \frac{7 + 34}{3}, t = \frac{7 - 34}{3}

5 = \frac{2}{3} (8 x - 6)

3 e^{- 3}

(x^{2})^{\frac{2}{5}}

32

\frac{1}{\frac{1}{6}}

What are the solutions to the equation 3t^2-14t+5=0 ?
The solutions to the equation 3t^2-14t+5=0 are t=(7+sqrt(34))/3 ,t=(7-sqrt(34))/3
Find the zeros of 3t^2-14t+5=0
The zeros of 3t^2-14t+5=0 are t=(7+sqrt(34))/3 ,t=(7-sqrt(34))/3