What is l[(2(s+1))/((s^2+2s+2)^2)] ?

The solution to l[(2(s+1))/((s^2+2s+2)^2)] is (2l(s+1))/((s^2+2s+2)^2)

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simplify l[(2(s+1))/((s^2+2s+2)^2)]

simplify

l [\frac{2 ( s + 1 )}{( s ^{2} + 2 s + 2 ) ^{2}}]

\frac{2 l ( s + 1 )}{( s ^{2} + 2 s + 2 ) ^{2}}

Solution steps

l (\frac{2 ( s + 1 )}{( s ^{2} + 2 s + 2 ) ^{2}})

Apply rule:

(a) = a

(\frac{2 ( s + 1 )}{( s ^{2} + 2 s + 2 ) ^{2}}) = \frac{2 ( s + 1 )}{( s ^{2} + 2 s + 2 ) ^{2}}

= l \frac{2 ( s + 1 )}{( s ^{2} + 2 s + 2 ) ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{l \cdot 2 ( s + 1 )}{( s ^{2} + 2 s + 2 ) ^{2}}

= \frac{2 l ( s + 1 )}{( s ^{2} + 2 s + 2 ) ^{2}}

(a + b) 2 + c

x^{- 7} 80 x - 8000

\frac{( 5 ^{n + 2} - 2 \cdot 5 ^{n} )}{( 23 \cdot 5 ^{n} )}

(\frac{x + y}{x})^{2}

\frac{5 a ^{m} ( 5 b ^{m} ) ^{2}}{( a ^{2} m ) ^{2}}

What is l[(2(s+1))/((s^2+2s+2)^2)] ?
The solution to l[(2(s+1))/((s^2+2s+2)^2)] is (2l(s+1))/((s^2+2s+2)^2)