What is (18x^2-10y^2*4x^4y^5)/(xy) ?

The solution to (18x^2-10y^2*4x^4y^5)/(xy) is (2x(9-20x^2y^7))/y

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simplify (18x^2-10y^2*4x^4y^5)/(xy)

simplify

\frac{18 x ^{2} - 10 y ^{2} \cdot 4 x ^{4} y ^{5}}{x y}

\frac{2 x ( 9 - 20 x ^{2} y ^{7} )}{y}

Solution steps

\frac{18 x ^{2} - 10 y ^{2} \cdot 4 x ^{4} y ^{5}}{x y}

Simplify

10 y^{2} \cdot 4 x^{4} y^{5} : 40 y^{7} x^{4}

= \frac{18 x ^{2} - 40 y ^{7} x ^{4}}{x y}

Factor

18 x^{2} - 40 x^{4} y^{7} : 2 x^{2} (9 - 20 x^{2} y^{7})

= \frac{2 x ^{2} ( 9 - 20 x ^{2} y ^{7} )}{x y}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{2} = xx

= \frac{2 xx ( 9 - 20 x ^{2} y ^{7} )}{x y}

Cancel the common factor:

x

= \frac{2 x ( 9 - 20 x ^{2} y ^{7} )}{y}

(2 x - y + z)^{3}

\frac{( x ^{2} + 2 x y + y ^{2} - 9 c ^{2} )}{( x + y - 3 c )}

\frac{( 2 x ^{2} )}{sin ( x )}

\frac{( - \frac{3}{8} ) \cdot ( - 3 ) x - 2}{7}

(\frac{( a ^{- 2} )}{( b ^{- 2} )}) \cdot (\frac{b}{a})^{3}

What is (18x^2-10y^2*4x^4y^5)/(xy) ?
The solution to (18x^2-10y^2*4x^4y^5)/(xy) is (2x(9-20x^2y^7))/y