What is ((3x^5)/y)^{-2} ?

The solution to ((3x^5)/y)^{-2} is (y^2)/(9x^{10)}

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simplify ((3x^5)/y)^{-2}

simplify

(\frac{3 x ^{5}}{y})^{- 2}

\frac{y ^{2}}{9 x ^{10}}

Solution steps

(\frac{3 x ^{5}}{y})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{3 x ^{5}}{y})^{- 2} = \frac{1}{( \frac{3 x ^{5}}{y} ) ^{2}}

= \frac{1}{( \frac{3 x ^{5}}{y} ) ^{2}}

Simplify

(\frac{3 x ^{5}}{y})^{2} : \frac{9 x ^{10}}{y ^{2}}

= \frac{1}{\frac{9 x ^{10}}{y ^{2}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{y ^{2}}{9 x ^{10}}

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