What is (2+3i)/(2-3i) ?

The solution to (2+3i)/(2-3i) is -5/13+12/13 i

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simplify (2+3i)/(2-3i)

simplify

\frac{2 + 3 i}{2 - 3 i}

- \frac{5}{13} + \frac{12}{13} i

Solution steps

\frac{2 + 3 i}{2 - 3 i}

Multiply by the conjugate

\frac{2 + 3 i}{2 + 3 i}

= \frac{( 2 + 3 i ) ( 2 + 3 i )}{( 2 - 3 i ) ( 2 + 3 i )}

Simplify

\frac{( 2 + 3 i ) ( 2 + 3 i )}{( 2 - 3 i ) ( 2 + 3 i )} : \frac{12 i - 5}{13}

= \frac{12 i - 5}{13}

Rewrite in standard complex form:

- \frac{5}{13} + \frac{12}{13} i

= - \frac{5}{13} + \frac{12}{13} i

3 (x - 9) = 18

\frac{y}{2} + \frac{5}{2} = \frac{y}{4}

lo g_{5} (\frac{1}{125}) = - 3

(1 + \frac{1}{x})^{2} - (1 - \frac{1}{x})^{2}

14 a^{4} b^{2} - 21 a^{3} b^{2}