What are the solutions to the equation 3d^2+d-10=0 ?

The solutions to the equation 3d^2+d-10=0 are d= 5/3 ,d=-2

Find the zeros of 3d^2+d-10=0

The zeros of 3d^2+d-10=0 are d= 5/3 ,d=-2

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3 d^{2} + d - 10 = 0

d = \frac{5}{3}, d = - 2

Solution steps

3 d^{2} + d - 10 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 10) = 11

d_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 3}

Separate the solutions

d_{1} = \frac{- 1 + 11}{2 \cdot 3}, d_{2} = \frac{- 1 - 11}{2 \cdot 3}

d = \frac{- 1 + 11}{2 \cdot 3} : \frac{5}{3}

d = \frac{- 1 - 11}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

d = \frac{5}{3}, d = - 2

\frac{1}{4} (5)

\frac{x}{2} = 50

\frac{1}{2} (25)

∣ 3 x - 1 ∣ + 1 = 1

∣ 3 x + 1 ∣ = - 4

What are the solutions to the equation 3d^2+d-10=0 ?
The solutions to the equation 3d^2+d-10=0 are d= 5/3 ,d=-2
Find the zeros of 3d^2+d-10=0
The zeros of 3d^2+d-10=0 are d= 5/3 ,d=-2